JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
For a given chemical \(A \rightarrow B\) at \(300\, \mathrm{~K}\) the free energy change is \(-49.4\, \mathrm{~kJ} \,\mathrm{~mol}^{-1}\) and the enthalpy of reaction is \(51.4\, \mathrm{~kJ} \,\mathrm{~mol}^{-1}\). The entropy change of the reaction is \(.....\,\mathrm{J}\, \mathrm{K}^{-1}\, \mathrm{~mol}^{-1} .\)
- A \(360\)
- B \(390\)
- C \(460\)
- D \(551\)
Answer & Solution
Correct Answer
(A) \(360\)
Step-by-step Solution
Detailed explanation
Given chemical reaction: \(\mathrm{A} \underset{\mathrm{T}\, 300\, \mathrm{~K}}{\longrightarrow} \mathrm{B}\) \([\Delta \mathrm{G}]_{\mathrm{P}, \mathrm{T}}=-49.4\, \mathrm{~kJ} / \mathrm{mol}\) \(\Delta \mathrm{H}_{\mathrm{rxn}}=51.4 \,\mathrm{~kJ} / \mathrm{mol}\)…
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