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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

આપેલ \(E^o_{Cl_2/Cl^-} = 1.36\,V,\)   \(E^o_{Cr^{3+}/Cr}= -0.74\,V,\) \(E^o_{Cr_2/O_7^{2-}/Cr^{3+}}=1.33\,V,\)   \(E^o_{MnO^-_4/Mn^{2+}} = 1.51\,V\) તો નીચેના પૈકી સૌથી પ્રબળ રિડક્શતકર્તા ..........

  1. A \(Cr\)
  2. B \(Mn^{2+}\)
  3. C \(Cr^{+3}\)
  4. D \(Cl^-\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(Cr\)

Step-by-step Solution

Detailed explanation

Lower the reduction potential, greater is the tendency of the element to get oxidized, hence, greater is the reducing ability. Since, chromium system has lowest reduction potential; therefore, it is the strongest reducing agent.
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