JEE Mains · Physics · STD 12 -7. Alternating current
For a series \(LCR\) circuit with \({R}=100\,\ \Omega, {L}=0.5\, {mH}\) and \({C}=0.1\, {pF}\) connected across \(220 \,{V}-50\, {Hz}\) \(AC\) supply, the phase angle between current and supplied voltage and the nature of the circuit is :
- A \(\approx 90^{\circ}\), predominantly inductive circuit
- B \(0^{\circ}\), resistive circuit
- C \(0^{\circ}\), resonance circuit
- D \(\approx 90^{\circ}\), predominantly capacitive circuit
Answer & Solution
Correct Answer
(D) \(\approx 90^{\circ}\), predominantly capacitive circuit
Step-by-step Solution
Detailed explanation
\(R=100\, \Omega\) \(X_{L}=\omega L=50 \pi \times 10^{-3}\) \(X_{c}=\frac{1}{\omega C}=\frac{10^{11}}{100 \pi}\) \(X_{c} \gg X_{L}\) \(\&\,\left|X_{c}-X_{L}\right| \gg R\)
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