JEE Mains · Chemistry · STD 12 - 10. Biomolecules

Given below are two statements:
Statement I: Sucrose is dextrorotatory. However sucrose upon hydrolysis gives a solution having mixture of products. This solution showing laevorotation.
Statement II: Hydrolysis of sucrose gives glucose and fructose. Since the laevorotation of glucose is more than the dextrorotation of fructose the resulting solution becomes laevorotatory.
In the light of the above statements, choose the correct answer from the options given below.

A Statement I is false but Statement II is true.
B Both Statement I and Statement II are false.
C Both Statement I and Statement II are true.
D Statement I is true but Statement II is false.

Verified Solution

Answer & Solution

Correct Answer

(D) Statement I is true but Statement II is false.

Step-by-step Solution

Detailed explanation

\(\begin{array}{r} C _{12} H _{22} O _{11}+ H _2 O \xrightarrow{ HCl } C _6 H _{12} O _6+ C _6 H _{12} O _6 \\ \text { D- Glucose + D fructose }\end{array}\) \([\alpha]_{D \text {-sucrose }}=+66.5^{\circ}, \quad[\alpha]_{D \text {-Glucose }}=+52.5^{\circ}\),…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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