JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2021
- Medium
- MCQ
A light beam is described by \(E=800 \sin \omega\left(t-\frac{x}{c}\right)\) An electron is allowed to move normal to the propagation of light beam with a speed of \(3 \times 10^{7}\;{ms}^{-1}\). What is the maximum magnetic force exerted on the electron ?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(12.8 \times 10^{-18} \,{N}\)
Step-by-step Solution
Detailed explanation
\(\frac{{E}_{0}}{{C}}={B}_{0}\)
\({F}_{\max }={eB}_{0} {V}\)
\(=1.6 \times 10^{-19} \times \frac{800}{3 \times 10^{8}} \times 3 \times 10^{7}\)
\(=12.8 \times 10^{-18}\, {N}\)
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