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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2021
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  • MCQ

A light beam is described by \(E=800 \sin \omega\left(t-\frac{x}{c}\right)\) An electron is allowed to move normal to the propagation of light beam with a speed of \(3 \times 10^{7}\;{ms}^{-1}\). What is the maximum magnetic force exerted on the electron ?

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Answer & Solution

Correct Answer

(D) \(12.8 \times 10^{-18} \,{N}\)

Step-by-step Solution

Detailed explanation

\(\frac{{E}_{0}}{{C}}={B}_{0}\)

\({F}_{\max }={eB}_{0} {V}\)

\(=1.6 \times 10^{-19} \times \frac{800}{3 \times 10^{8}} \times 3 \times 10^{7}\)

\(=12.8 \times 10^{-18}\, {N}\)

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