JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A ray of light passing through a prism \((\mu=\sqrt{3})\) suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. Then, the angle of prism is ..... . (in degrees)
- A \(50\)
- B \(80\)
- C \(30\)
- D \(60\)
Answer & Solution
Correct Answer
(D) \(60\)
Step-by-step Solution
Detailed explanation
At minimum deviation \(r_{1}=r_{2}=\frac{A}{2}\) Also given \({i}=2 {r}_{1}={A}\) Now \(1 \sin i =\sqrt{3} \sin r_{1}\) \(1 \sin A=\sqrt{3} \sin \frac{A}{2}\) \(2 \sin \frac{A}{2} \cos \frac{A}{2}=\sqrt{3} \sin \frac{A}{2}\)…
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