JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
\(t _{87.5}\) is the time required for the reaction to undergo \(87.5 \%\) completion and \(t_{50}\) is the time required for the reaction to undergo \(50 \%\) completion. The relation between \(t_{87.5}\) and \(t_{50}\) for a first order reaction is \(t _{87.5}= x \times t _{50}\) The value of \(x\) is \(......\). (Nearest integer)
- A \(4\)
- B \(2\)
- C \(3\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(A _{ t }= A _0 \times \frac{12.5}{100}=\frac{ A _0}{8} \quad[87.5 \% \text { complete }]\) \(A _0 \stackrel{ t _{1 / 2}}{\longrightarrow} \frac{ A _0}{2} \stackrel{ t _{ H / 2}}{\longrightarrow} \frac{ A _0}{4} \stackrel{ t _{ L / 2}}{\longrightarrow} \frac{ A _0}{8}\)…
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