JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Gas 'A' undergoes change from state 'X' to state 'Y'. In this process, the heat absorbed and work done by the gas is \(10\) J and \(18\) J respectively. Now gas is brought back to state 'X' by another process during which \(6\) J of heat is evolved. In the reverse process of 'Y' to 'X',
- A \(18\) J of the work is done by the gas 'A'.
- B \(2\) J of the work is done by the gas 'A'.
- C \(12\) J of the work is done on the gas 'A' by the surrounding.
- D \(14\) J of the work is done on the gas 'A' by the surrounding.
Answer & Solution
Correct Answer
(D) \(14\) J of the work is done on the gas 'A' by the surrounding.
Step-by-step Solution
Detailed explanation
Using the first law of thermodynamics, \(\Delta U = q + w\). For the process from state X to state Y: Heat absorbed by the gas, \(q_{X \to Y} = +10\) J Work done by the gas, \(w_{X \to Y} = -18\) J Change in internal energy,…
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