JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2022
- Medium
- Numerical
\(0.056 \,kg\) of Nitrogen is enclosed in a vessel at a temperature of \(127\,^{\circ} C\). The amount of heat required to double the speed of its molecules is k cal. (Take \(R =2\) \(cal \,mole\) \(^{-1} K ^{-1}\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(0.056 \,kg N N _{2}=56\, gm\) of \(N _{2}=2\, mole\) of \(N _{2}\)
\(T _{1}=400\, K , v \alpha \sqrt{ T }\) so \(T _{2}=4 T _{1}=1600\, K\)
\(Q =\frac{ f }{2} nR \Delta T\)
\(f=5\)
\(Q =12 \,k \,cal\)
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