JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
For a short dipole placed at origin \(O\), the dipole moment \(P\) is along \(x\)-axis, as shown in the figure. If the electric potential and electric field at A are \(\mathrm{V}_0\) and \(\mathrm{E}_0\), respectively, then the correct combination of the electric potential and electric field, respectively, at point \(B\) on the \(y\)-axis is given by...
- A \(V_0\) and \(\frac{E_0}{4}\)
- B zero and \(\frac{E_0}{16}\)
- C zero and \(\frac{E_0}{8}\)
- D \(\frac{\mathrm{V}_0}{2}\) and \(\frac{\mathrm{E}_0}{16}\)
Answer & Solution
Correct Answer
(B) zero and \(\frac{E_0}{16}\)
Step-by-step Solution
Detailed explanation
At point \(A\) (axial) \(\left|E_0\right|=\frac{2 k_p}{r^3}, V_0=\frac{k_p}{r^2}\) At point \(B\) (equatorial) \(\begin{aligned} & |E|=\frac{k_p}{(2 r)^3}=\frac{E_0}{16} \\ & V=0 \end{aligned}\)
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