JEE Mains · Chemistry · STD 11 - 2. structure of atom
Consider two radiations of wavelengths
1. \(\lambda_1 = 2000\) Å
2. \(\lambda_2 = 6000\) Å
The ratio of the energies of these two radiations \(\left(\dfrac{E_1}{E_2}\right)\) is ________ (Nearest integer).
- A 2
- B 3
- C 4
- D 5
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
The energy of a photon is given by the relation: \(E = \dfrac{hc}{\lambda}\) For the two radiations, the energies are \(E_1 = \dfrac{hc}{\lambda_1}\) and \(E_2 = \dfrac{hc}{\lambda_2}\). The ratio of their energies is: \(\dfrac{E_1}{E_2} = \dfrac{\lambda_2}{\lambda_1}\)…
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