JEE Mains · Physics · STD 11 - 11. thermodynamics
For an ideal heat engine, the temperature of the source is \(127\,^{\circ} C\). In order to have \(60\, \%\) efficiency the temperature of the sink should be \(........\,{ }^{\circ} C\). (Round off to the Nearest Integer)
- A \(-\,113\)
- B \(121\)
- C \(107\)
- D \(128\)
Answer & Solution
Correct Answer
(A) \(-\,113\)
Step-by-step Solution
Detailed explanation
\(n =0.60=1=\frac{ T _{ L }}{ T _{ H }}\) \(\frac{ T _{ L }}{ T _{ H }}=0.4 \Rightarrow T _{ L }=0.4 \times 400\) \(=160\, K\) \(=-113\,^{\circ} C\)
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