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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2021
  • Medium
  • MCQ

For an ideal heat engine, the temperature of the source is \(127\,^{\circ} C\). In order to have \(60\, \%\) efficiency the temperature of the sink should be \(........\,{ }^{\circ} C\). (Round off to the Nearest Integer)

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Answer & Solution

Correct Answer

(A) \(-\,113\)

Step-by-step Solution

Detailed explanation

\(n =0.60=1=\frac{ T _{ L }}{ T _{ H }}\)

\(\frac{ T _{ L }}{ T _{ H }}=0.4 \Rightarrow T _{ L }=0.4 \times 400\)

\(=160\, K\)

\(=-113\,^{\circ} C\)

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