JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2021
- Medium
- MCQ
For an ideal heat engine, the temperature of the source is \(127\,^{\circ} C\). In order to have \(60\, \%\) efficiency the temperature of the sink should be \(........\,{ }^{\circ} C\). (Round off to the Nearest Integer)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(-\,113\)
Step-by-step Solution
Detailed explanation
\(n =0.60=1=\frac{ T _{ L }}{ T _{ H }}\)
\(\frac{ T _{ L }}{ T _{ H }}=0.4 \Rightarrow T _{ L }=0.4 \times 400\)
\(=160\, K\)
\(=-113\,^{\circ} C\)
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