JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
If the \(pKa\) of lactic acid is \(5\),then the \(pH\) of \(0.005\) \(M\) calcium lactate solution at \(25^{\circ}\,C\) is \(........\times 10^{-1}\) (Nearest integer)
- A \(85\)
- B \(84\)
- C \(83\)
- D \(82\)
Answer & Solution
Correct Answer
(A) \(85\)
Step-by-step Solution
Detailed explanation
Concentration of calcium lactate \(=0.005\,M ,:\) concentration of lactate ion \(=(2 \times 0.005)\,M\). Calcium lactate is a salt of weak acid \(+\) strong base \(\therefore\) Salt hydrolysis will take place. \(pH =7+\frac{1}{2}( pKa +\log C )\)…
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