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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
An \(\alpha\) particle and a proton are accelerated from rest by a potential difference of \(200\, V\). After this, their de Broglie wavelengths are \(\lambda_{\alpha}\) and \(\lambda_{p}\) respectively. The ratio \(\frac{\lambda_{p}}{\lambda_{a}}\) is
- A \(3.8\)
- B \(8\)
- C \(7.8\)
- D \(2.8\)
Answer & Solution
Correct Answer
(D) \(2.8\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{ h }{ p }=\frac{ h }{\sqrt{2 m q V }}\) \(\frac{\lambda_{ p }}{\lambda_{\alpha}}=\sqrt{\frac{ m _{\alpha} q _{a}}{ m _{ p } q _{ p }}}=\sqrt{\frac{4 m _{ p } \times 2 e }{ m _{ p } \times e }}=\sqrt{8}=2 \sqrt{2}\) \(=2 \sqrt{2}\)…
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