JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For the following reactions.....\(kJ/mol\) \(\mathrm{A} \stackrel{700 \mathrm{K}}{\rightarrow}\) Product \(\mathrm{A}\xrightarrow[\text { catalyst }]{500 \mathrm{K}} \) Product it was found that \(\mathrm{E}_{\mathrm{a}}\) is decreased by \(30 \;\mathrm{kJ} / \mathrm{mol}\) in the presence of catalyst. If the rate remains unchanged, the activation energy for catalysed reaction is (Assume pre exponential factor is same \():\)
- A \(135\)
- B \(105\)
- C \(198\)
- D \(75\)
Answer & Solution
Correct Answer
(D) \(75\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{1}=\mathrm{Ae}^{-\frac{\mathrm{Ea}}{\mathrm{R} \times 700}}\) \(\mathrm{K}_{2}=\mathrm{A} \times \mathrm{e}^{-\frac{(\mathrm{Ea}-30)}{\mathrm{R} \times 500}}\) For same rate \(\mathrm{K}_{1}=\mathrm{K}_{2}\)…
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