JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
During the nuclear explosion, one of the products is \(^{90} \mathrm{Sr}\) with half life of \(6.93\) years. if \(1 \;\mu g\) of \(^{90} \mathrm{Sr}\) was absorbed in the bones of a newly born baby in place of \(Ca\), how much time, in years, is required to reduce it by \(90 \%\) if it is not lost metabolically
- A \(27.01\)
- B \(25.07\)
- C \(23.03\)
- D \(21.06\)
Answer & Solution
Correct Answer
(C) \(23.03\)
Step-by-step Solution
Detailed explanation
All nuclear decays follow first order kinetics \(\mathrm{t}=\frac{1}{\mathrm{k}} \ln \frac{\left[\mathrm{A}_{0}\right]}{[\mathrm{A}]}\) \(=\frac{\left(t_{1 / 2}\right)}{0.693} \times 2.303 \quad \log _{10} 10=10 \times 2.303 \times 1\) \(=23.03\) years
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