JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
For the equilibrium \(2{H_2}O \rightleftharpoons {H_3}{O^ + } + O{H^ - }\) , the value of \(\Delta {G^o}\) at \(298\,K\) is approximately .......\(kJ\,mol^{-1}\)
- A \(100\)
- B \(-80\)
- C \(80\)
- D \(-100\)
Answer & Solution
Correct Answer
(C) \(80\)
Step-by-step Solution
Detailed explanation
\(\Delta {G^o} = - 2.303RT\,\log \,{K_{eq}}\) \( = - 2.303 \times 8.314 \times 298\,\log \,{10^{ - 14}}\) \( = - 2.303 \times 8.314 \times 298 \times - 14\) \( = 79,881.87\) \( \simeq 80\,KJ\,mo{l^{ - 1}}\)
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