JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Consider the reaction \({N_2}(g)\, + 3{H_2}(g)\, \rightleftharpoons \,2N{H_3}(g)\) The equilibrium constant of the above reaction is \(K_3\). If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that \(P_{NH_3}<\,< P_{total}\) at equilibrium)
- A \(\frac{{{3^{3/2}}K_p^{1/2}{P^2}}}{{16}}\)
- B \(\frac{{K_p^{1/2}{P^2}}}{16}\)
- C \(\frac{{K_p^{1/2}{P^2}}}{4}\)
- D \(\frac{{{3^{3/2}}K_p^{1/2}{P^2}}}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{{{3^{3/2}}K_p^{1/2}{P^2}}}{{16}}\)
Step-by-step Solution
Detailed explanation
\(\mathop {{N_2}}\limits_x + \mathop {3{H_2}}\limits_{3x} \leftrightarrow \mathop {2N{H_3}}\limits_{{P_1}} \) \({P_T} = 4x\,{K_P} = \frac{{P_1^2}}{{x \times 27 \times 3}}\) \(x = \left( {\frac{P}{4}} \right)\) \({P_1} = \sqrt {27{X^4}{K_P}} \)…
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