JEE Mains · Chemistry · STD 11 - 2. structure of atom
Energy of an electron is given by \(E =- 2.178 \times 10^{-18}\,J \, \left( {\frac{{{Z^2}}}{{{n^2}}}} \right) .\) Wavelength of light required to excite an electron in an hydrogen atom from level \(n = 1\) to \(n = 2\) will be : \((h = 6.62 \times 10^{-34} \,Js\) and \(c = 3.0 \times 10^8 \,ms^{-1})\)
- A \(1.214 \times 10^{-7} \,m\)
- B \(2.816 \times 10^{-7}\, m\)
- C \(6.500 \times 10^{-7}\, m\)
- D \(8.500 \times 10^{-7}\, m\)
Answer & Solution
Correct Answer
(A) \(1.214 \times 10^{-7} \,m\)
Step-by-step Solution
Detailed explanation
Let \(\lambda\) is the wavelength of that photon then \(h c / \lambda=E_{2}-E_{1}\) and using value of given E, \(E=\frac{h c}{\lambda}=2.178 \times 10^{-18} \times z^{2}\left[\frac{1}{1^{2}}-\frac{1}{2^{2}}\right](z=1)\)…
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