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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

A 2 A current carrying straight metal wire of resistance \(1 \Omega\), resistivity \(2 \times 10^{-6} \Omega m\), area of cross-section \(10 mm^2\) and mass 500 g is suspended horizontally in mid air by applying a uniform magnetic field \(\vec{B}\). The magnitude of \(B\) is _______ \(\times 10^{-1} T\) (given, \(g =10 m / s ^2\) ).

  1. A 5
  2. B 10
  3. C 15
  4. D 20
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Answer & Solution

Correct Answer

(A) 5

Step-by-step Solution

Detailed explanation

\(R=\frac{\rho \ell}{A} \Rightarrow \frac{2 \times 10^{-6} \times \ell}{10^{-5}}=1 \Rightarrow \ell=5\) \(mg = Bi \ell\) \(B =\frac{ mg }{ i \ell}=\frac{5}{2 \times 5}=0.5=5 \times 10^{-1}\) Tesla
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