JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Elevation in the boiling point for \(1\) molal solution of glucose is \(2\, K\). The depression in the freezing point for \(2\) molal solution of glucose in the same solvent is \(2\, K\). The relation between \(K_b\) and \(K_f\) is
- A \(K_b = 1.5K_f\)
- B \(K_b = K_f\)
- C \(K_b = 0.5K_f\)
- D \(K_b = 2K_f\)
Answer & Solution
Correct Answer
(D) \(K_b = 2K_f\)
Step-by-step Solution
Detailed explanation
\(\Delta {T_b}\, = \,{K_b}m\) \(\Delta {T_b}\, = \,{K_b}\, \times \,1\, \Rightarrow \,2\, = \,{K_b}\) \(\Delta {T_f}\, = \,{K_f}m\) \(2\, = \,2{K_f}\, = \,{K_f}\) \(\frac{{{K_f}}}{{{K_b}}}\, = \,\frac{1}{2}\)
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