JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(80\) mole percent of \(MgCl _2\) is dissociated in aqueous solution. The vapour pressure of \(1.0\) molal aqueous solution of \(MgCl _2\) at \(38^{\circ} C\) is \(.........\,mm\,Hg\). (Nearest integer)Given : Vapour pressure of water at \(38^{\circ} C\) is \(50\,mm\,Hg\)
- A \(47\)
- B \(48\)
- C \(46\)
- D \(45\)
Answer & Solution
Correct Answer
(B) \(48\)
Step-by-step Solution
Detailed explanation
\(MgCl _2 \rightarrow Mg ^{+2}+2 Cl ^{-}\) \(1-\alpha \quad \alpha \quad 2 \alpha\) \(i =1+2 \alpha(\alpha=0.8)\) \(i =2.6\) \(\frac{\Delta p }{ p ^{\circ}}=\frac{ i \times n _2}{ n _1}\) \(\Delta p =2.34\) \(p _s=47.66\) \(p _{ s } \cong 48\)
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