JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
At \(300\, K\), the vapour pressure of a solution containing \(1\) mole of \(n-\)hexane and \(3\) moles of \(n-\)heptane is \(550\, mm\) of \(Hg\). At the same temperature, if one more mole of n-heptane is added to this solution, the vapour pressure of the solution increases by \(10\, mm\) of \(Hg\). What is the vapour pressure in \(mm Hg\) of \(n-\)heptane in its pure state..........\(?\)
- A \(600\)
- B \(620\)
- C \(590\)
- D \(628\)
Answer & Solution
Correct Answer
(A) \(600\)
Step-by-step Solution
Detailed explanation
\(550= P _{ A }^{\circ} \times \frac{1}{4}+ P _{ B }^{\circ} \times \frac{3}{4}\) \(2200= P _{ A }^{\circ}+3 P _{ B }^{\circ}\)\(....(i)\) \(2800= P _{ A }^{\circ}+4 P _{ B }^{\circ}\)\(....(ii)\) \(560= P _{ A }^{\circ} \times \frac{1}{5}+ P _{ B }^{\circ} \times \frac{4}{5}\)…
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