JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Consider the following data for the reaction
\(X_2(g) + Y_2(g) \rightleftharpoons 2XY(g)\)
at \(600\text{ K}\). The \(\Delta_r G^\circ\) (in kJ mol\(^{-1}\)) for the reaction is :
| Compound | \(\Delta_f H^\circ_{600K}\) (kJ mol\(^{-1}\)) | \(S^\circ_{600K}\) (J mol\(^{-1}\) K\(^{-1}\)) |
|---|---|---|
| \(XY(g)\) | \(42\) | \(200\) |
| \(X_2(g)\) | \(8\) | \(140\) |
| \(Y_2(g)\) | \(80\) | \(250\) |
- A \(-21000\)
- B \(-10\)
- C \(-1000\)
- D \(-9.012\)
Answer & Solution
Correct Answer
(B) \(-10\)
Step-by-step Solution
Detailed explanation
The given reaction is \(X_2(g) + Y_2(g) \rightleftharpoons 2XY(g)\). The standard enthalpy of reaction, \(\Delta_r H^\circ\), is calculated as: \(\Delta_r H^\circ = \sum \Delta_f H^\circ(\text{products}) - \sum \Delta_f H^\circ(\text{reactants})\)…
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