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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

Consider the following data for the reaction
\(X_2(g) + Y_2(g) \rightleftharpoons 2XY(g)\)
at \(600\text{ K}\). The \(\Delta_r G^\circ\) (in kJ mol\(^{-1}\)) for the reaction is :
Compound\(\Delta_f H^\circ_{600K}\) (kJ mol\(^{-1}\))\(S^\circ_{600K}\) (J mol\(^{-1}\) K\(^{-1}\))
\(XY(g)\)\(42\)\(200\)
\(X_2(g)\)\(8\)\(140\)
\(Y_2(g)\)\(80\)\(250\)

  1. A \(-21000\)
  2. B \(-10\)
  3. C \(-1000\)
  4. D \(-9.012\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-10\)

Step-by-step Solution

Detailed explanation

The given reaction is \(X_2(g) + Y_2(g) \rightleftharpoons 2XY(g)\). The standard enthalpy of reaction, \(\Delta_r H^\circ\), is calculated as: \(\Delta_r H^\circ = \sum \Delta_f H^\circ(\text{products}) - \sum \Delta_f H^\circ(\text{reactants})\)…
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