JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Consider the following data.
(i) \(2Al(s) + 6HCl(aq) \rightarrow Al_2Cl_6(aq) + 3H_2(g) + 1200\) kJ/mol
(ii) \(H_2(g) + Cl_2(g) \rightarrow 2HCl(g) + 164\) kJ/mol
(iii) \(HCl(g) + aq \rightarrow HCl(aq) + 83\) kJ/mol
(iv) \(Al_2Cl_6(s) + aq \rightarrow Al_2Cl_6(aq) + 663\) kJ/mol
The enthalpy of formation of anhydrous solid \(Al_2Cl_6\) is :
- A \(-648\) kJ mol\(^{-1}\)
- B \(-1350\) kJ mol\(^{-1}\)
- C \(-2002\) kJ mol\(^{-1}\)
- D \(-1527\) kJ mol\(^{-1}\)
Answer & Solution
Correct Answer
(D) \(-1527\) kJ mol\(^{-1}\)
Step-by-step Solution
Detailed explanation
The given reactions with their enthalpy changes are: (i) \(2Al(s) + 6HCl(aq) \rightarrow Al_2Cl_6(aq) + 3H_2(g)\), \(\Delta H_1 = -1200\) kJ/mol (ii) \(H_2(g) + Cl_2(g) \rightarrow 2HCl(g)\), \(\Delta H_2 = -164\) kJ/mol (iii) \(HCl(g) + aq \rightarrow HCl(aq)\),…
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