JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Consider the following data:
\(\Delta_{f}H^{\Theta}(methane,g) = -X~kJ~mol^{-1}\)
Enthalpy of sublimation of graphite = \(Y~kJ~mol^{-1}\)
Dissociation enthalpy of \(H_{2} = Z~kJ~mol^{-1}\)
The bond enthalpy of C-H bond is given by:
- A \(\frac{X+Y+2Z}{4}\)
- B \(\frac{X+Y+4Z}{2}\)
- C \(X+Y+Z\)
- D \(\frac{-X+Y+Z}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{X+Y+2Z}{4}\)
Step-by-step Solution
Detailed explanation
\(C ( s )+2 H _2(g) \rightarrow CH _4(g)\) \(-x=\left(\Delta H_{\text {sub }}\right.\) of carbon \()+2 \times(\) B.E. of \(H-H)\) \(-4 \times(\) B.E. of \(C - H )\) \(-x=y+2 z-4(\) B.E. of \(C-H)\) B.E. of \(C - H =\frac{ y +2 z + x }{4}\).
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