JEE Mains · Chemistry · STD 11 - 2. structure of atom
For any given series of spectral lines of atomic hydrogen, let \(\Delta \bar V\, = \,\Delta {\bar V_{\max }}\, - \,\Delta {\bar V_{\min }}\) be the difference in maximum and minimum frequencies in \(cm^{-1}.\) the ration \(\Delta {\bar V_{Lymann}}/\,\Delta {\bar V_{Balmer}}\) is
- A \(5:4\)
- B \(4:1\)
- C \(9:4\)
- D \(27:5\)
Answer & Solution
Correct Answer
(C) \(9:4\)
Step-by-step Solution
Detailed explanation
\(\Delta {{\bar V}_{Lymann}} = \frac{{{R_H}}}{4}\) \(\Delta {{\bar V}_{Balmer}} = \frac{{{R_H}}}{9}\) \( \Rightarrow \frac{{\Delta {{\bar V}_{Lymann}}}}{{\Delta {{\bar V}_{Balmer}}}} = \frac{9}{4}\) Formula…
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