JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
For the reaction, \( N_{2}O_{4}\rightleftharpoons 2NO_{2}, \) graph is plotted as shown below. Identify correct statements.
A. Standard free energy change for the reaction is -5.40 kJ mol⁻¹.
B. As \( \Delta G^{\ominus} \) in graph is positive, \( N_{2}O_{4} \) will not dissociate into \( NO_{2} \) at all.
C. Reverse reaction will go to completion.
D. When 1 mole of \( N_{2}O_{4} \) changes into equilibrium mixture, value of \( \Delta G^{\ominus}=-0.84 \, kJ \, mol^{-1} \).
E. When 2 mole of \( NO_{2} \) changes into equilibrium mixture, \( \Delta G^{\ominus} \) for equilibrium mixture is -6.24 kJ mol⁻¹.
Choose the correct answer from the options given below:
- A D and E only
- B C and E only
- C A and D only
- D B and C only
Answer & Solution
Correct Answer
(A) D and E only
Step-by-step Solution
Detailed explanation
(A) \( \Delta_{r}G^{\circ} = G^{\circ}_{B} - G^{\circ}_{A} = +ve \) (B) \( \Delta_{r}G^{\circ} = +ve \). \( N_{2}O_{4} \) will partially dissociate into \( NO_{2} \). (C) For reverse reaction, It is partially completed as there is equilibrium at E. (D) For 1 mole…
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