JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Water decomposes at \(2300\,K\) \(H _2 O ( g ) \rightarrow H _2( g )+\frac{1}{2} O _2( g )\) The percent of water decomposing at \(2300\,K\) and \(1\,bar\) is \(...........\) (Nearest integer). Equilibrium constant for the reaction is \(2 \times 10^{-3}\) at \(2300\,K\)
- A \(2\)
- B \(4\)
- C \(6\)
- D \(8\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(H _2 O ( g ) \rightleftharpoons H _2( g )+\frac{1}{2} O _2( g )\) \(P _0[1-\alpha] \quad P _0 \alpha \quad \frac{ P _0 \alpha}{2} \quad \text { partial pr. at eq }\) \(P _0\left[1+\frac{\alpha}{2}\right]=1\)…
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