JEE Mains · Chemistry · STD 12 - p -Block elements - ll
Assertion : Nitrogen and oxygen are the main components in the atmosphere but these do not react to form oxides of nitrogen. Reason : The reaction between nitrogen and oxygen requires high temperature.
- A The assertion is incorrect, but the reason is correct
- B Both the assertion and reason are incorrect
- C Both assertion and reason are correct, and the reason is the correct explanation for the assertion
- D Both assertion and reason are correct, but the reason is not the correct explanation for the assertion
Answer & Solution
Correct Answer
(C) Both assertion and reason are correct, and the reason is the correct explanation for the assertion
Step-by-step Solution
Detailed explanation
Nitrogen and oxygen in air do not react to form oxides of nitrogen in atmosphere because the reaction between nitrogen and oxygen requires high temperature.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Given below are two statements : Statement \((I)\) : Kjeldahl method is applicable to estimate nitrogen in pyridine. Statement \((II)\) : The nitrogen present in pyridine can easily be converted into ammonium sulphate in Kjeldahl method. In the light of the above statements, choose the correct answer from the options given below.JEE Mains 2024 Medium
- Galvanization is applying a coating of :JEE Mains 2016 Easy
- The comect order of melting points of hydrides of group \(16\) elements is \(...\)JEE Mains 2022 Easy
- The correct statement with respect to dinitrogen isJEE Mains 2020 Medium
- For the reaction: \(RCH _2 Br + I ^{-} \stackrel{\text { Acetone }}{\longrightarrow} \underset{\text { major }}{ RCH _2 I + Br ^{-}}\) The correct statement is :JEE Mains 2023 Hard
- Given below are two statements: Statement \((I)\) : In the Lanthanoids, the formation of \(\mathrm{Ce}^{+4}\) is favoured by its noble gas configuration. Statement \((II)\) : \(\mathrm{Ce}^{+4}\) is a strong oxidant reverting to the common \(+3\) state. In the light of the above statements, choose the most appropriate answer from the options given below:JEE Mains 2024 Hard
More PYQs from JEE Mains
- The number of solutions of \(\sin ^{7} x+\cos ^{7}=1, x \in[0,4 \pi]\) is equal to :JEE Mains 2021 Hard
- In basic medium \(CrO _{4}^{2-}\) oxidises \(S _{2} O _{3}^{2-}\) to form \(SO _{4}^{2-}\) and itself changes into \(Cr ( OH )_{4}^{-}\). The volume of \(0.154\, M CrO _{4}^{2-}\) required to react with \(40\, mL\) of \(0.25\, M S _{2} O _{3}^{2-}\) is ........... \(mL\) (Rounded-off to the nearest integer)JEE Mains 2021 Easy
- Match List\(-I\) with List\(-II\)
The correct match isList\(-I\) Test/Reagents/Observation(s) List\(-II\) Species detected \((a)\) Lassaigne's Test \((i)\) Carbon \((b)\;Cu ( II )\) oxide \((ii)\) Sulphur \((c)\) Silver nitrate \((iii)\;N , S , P ,\) and halogen \((d)\) The sodium fusion extract gives black precipitate with acetic acid and lead acetate \((iv)\) Halogen Specifically JEE Mains 2021 Medium - An air bubble of volume \(1\,cm ^3\) rises from the bottom of a lake \(40\,m\) deep to the surface at a temperature of \(12^{\circ}\,C\). The atmospheric pressure is \(1 \times 10^5 Pa\), the density of water is \(1000\,kg / m ^3\) and \(g =10\,m / s ^2\). There is no difference of the temperature of water at the depth of \(40\,m\) and on the surface. The volume of air bubble when it reaches the surface will be \(..........\,cm^{3}\)JEE Mains 2023 Medium
- If \(a,\, b,\,c,\,d\) are inputs to a gate and \(x\) is its output, then, as per the following time graph, the gate is
JEE Mains 2016 Medium - For \(k \in N\), if the sum of the series \(1+\frac{4}{ k }+\frac{8}{ k ^2}+\frac{13}{ k ^3}+\frac{19}{ k ^4}+\ldots\) is 10 , then the value of \(k\) isJEE Mains 2023 Hard