JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Consider the following reaction occurring in the blast furnace:
\(\mathrm{Fe}_3 \mathrm{O}_{4(\mathrm{~s})}+4 \mathrm{CO}_{(\mathrm{g})} \rightarrow 3 \mathrm{Fe}_{(\mathrm{l})}+4 \mathrm{CO}_{2(\mathrm{~g})}\)
' \(x\) ' kg of iron is produced when \(2.32 \times 10^3 \mathrm{~kg} \mathrm{Fe}_3 \mathrm{O}_4\) and \(2.8 \times 10^2 \mathrm{~kg} \mathrm{CO}\) are brought together in the furnace. The value of ' \(x\) ' is _____. (nearest integer)
Given:
molar mass of \(\mathrm{Fe}_3 \mathrm{O}_4=232 \mathrm{~g} \mathrm{~mol}^{-1}\)
molar mass of \(\mathrm{CO}=28 \mathrm{~g} \mathrm{~mol}^{-1}\)
molar mass of \(\left.\mathrm{Fe}=56 \mathrm{~g} \mathrm{~mol}^{-1}\right\}\)
- A 400
- B 420
- C 440
- D 460
Answer & Solution
Correct Answer
(B) 420
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { moles of } \mathrm{Fe}_3 \mathrm{O}_4=\frac{2.32 \times 10^3 \times 10^3}{232}=10000 \mathrm{~mol} \\ & \text { moles of } \mathrm{CO}=\frac{2.8 \times 10^2 \times 10^3}{28}=10000 \mathrm{~mol} \\ & \mathrm{Fe}_3^3 \mathrm{O}_4+4 \mathrm{CO}…
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