JEE Mains · Chemistry · STD 12 - p -Block elements - ll

Chlorine water on standing loses its colour and forms

A \(HCl\) only
B \(HCl\) and \(HClO_2\)
C \(HCl\) and \(HOCl\)
D \(HOCl\) and \(HOCl_2\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(HCl\) and \(HOCl\)

Step-by-step Solution

Detailed explanation

Chlorinated water is yellow in colour on standing reaction occurs \(Cl_2 + H_2O \to HCl + HOCl\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List\(-I\) with List\(-II :\)

List\(-I\) (Species)	List\(-II\) (Hybrid Orbitals)
\((a)\) \(\mathrm{SF}_{4}\)	\((i)\) \(\mathrm{sp}^{3} \mathrm{~d}^{2}\)
\((b)\) \(\mathrm{IF}_{5}\)	\((ii)\) \(\mathrm{d}^{2} \mathrm{sp}^{3}\)
\((c)\) \(\mathrm{NO}_{2}^{+}\)	\((iii)\) \(\mathrm{sp}^{3} \mathrm{~d}\)
\((d)\) \(\mathrm{NH}_{4}^{+}\)	\((iv)\) \(\mathrm{sp}^{3}\)
	\((v)\) \(\mathrm{sp}\)

Choose the correct answer form the options given below :

JEE Mains 2021 Hard

Match List - I with List - II.

List - I Mixture of Compounds	List - II Reagent used to distinguish
A. Diethyl amine + Ethyl amine	I. Bromine water
B. Acetaldehyde + Acetone	II. \(CHCl_3 + KOH, \Delta\)
C. Ethanol + Phenol	III. Neutral \(FeCl_3\)
D. Benzoic acid + Cinnamic acid	IV. Ammonical silver nitrate

Choose the correct answer from the options given below :

JEE Mains 2026 Medium

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