JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The elemental composition of a compound is \(54.2 \% \mathrm{C}, 9.2 \% \mathrm{H}\) and \(36.6 \% \mathrm{O}\).
If the molar mass of the compound is \(132 \mathrm{~g} \mathrm{~mol}^{-1}\), the molecular formula of the compound is :
[Given : The relative atomic mass of \(\mathrm{C}: \mathrm{H}: \mathrm{O}=12: 1: 16\) ]
- A \(\mathrm{C}_4 \mathrm{H}_9 \mathrm{O}_3\)
- B \(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\)
- C \(\mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_2\)
- D \(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3\)
Answer & Solution
Correct Answer
(D) \(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3\)
Step-by-step Solution
Detailed explanation
Molecular mass of compound \(=132 \mathrm{~g} \mathrm{~mol}^{-1}\) Molecular formula of compound is \(\left(\mathrm{C}_2 \mathrm{H}_4 \mathrm{O}\right)_n\) \(\mathrm{n}=\frac{\text { Molecular mass }}{\mathrm{EF} \text { mass }}=\frac{132}{44}=3\) \(\therefore\) Molecular…
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