An iron rod of volume \(10^{-3}\, m ^{3}\) and relative permeability \(1000\) is placed as core in a solenoid with \(10\) \(turns/cm.\) If a current of \(0.5\, A\) is passed through the solenoid, then the magnetic moment of the rod will be\(...........Am^2\)

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Answer & Solution

Correct Answer

(D) \(5 \times 10^{2}\)

Step-by-step Solution

Detailed explanation

\(M =\mu_{ r } Ni A\)

Here

\(\mu_{ r }=\) Relative permeability

\(N =\) No. of turns

\(i =\) Current

\(A =\) Aea of cross section

\(M=\mu_{r} N i A=\mu_{r} n\ell i A\)

\(M=\mu_{r} n i V=1000(1000) 0.5\left(10^{-3}\right)\)

\(=500=5 \times 10^{2} Am ^{2}\)

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