JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the manganese product formed from the above reaction is \(....\,B.M.\) (Nearest Integer)
- A \(9\)
- B \(8\)
- C \(4\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
\(2 KMnO _{4}+5 H _{2} C _{2} O _{4}+3 H _{2} SO _{4} \rightarrow K _{2} SO _{4} + 2 MnSO _{4}+10 CO _{2}+8 H _{2} O\) \(Mn ^{2+}\) has \(5\) unpaired electrons therefore the magnetic moment is \(\sqrt{35}\, BM\)
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