JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A uniform chain of length \(3\, meter\) and mass \(3\, {kg}\) overhangs a smooth table with \(2\, meter\) laying on the table. If \(k\) is the kinetic energy of the chain in joule as it completely slips off the table, then the value of \({k}\) is (Take \(\left.g=10\, {m} / {s}^{2}\right)\)
- A \(40\)
- B \(60\)
- C \(400\)
- D \(10\)
Answer & Solution
Correct Answer
(A) \(40\)
Step-by-step Solution
Detailed explanation
From energy conservation \({K}_{{i}}+{U}_{{i}}={k}_{{f}}+{U}_{{f}}\) \(0+\left(-1 \times 10 \times \frac{1}{2}\right)={k}_{{f}}+\left(-3 \times 10 \times \frac{3}{2}\right)\) \(-5={k}_{{f}}-45\) \({k}_{{f}}=40 \,{J}\)
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