JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Sodium oxide reacts with water to produce sodium hydroxide. \(20.0\, \mathrm{~g}\) of sodium oxide is dissolved in \(500\, \mathrm{~mL}\) of water. Neglecting the change in volume, the concentration of the resulting \(\mathrm{NaOH}\) solution is \(........\times \quad 10^{-1} \quad\) \(M.\) (Nearest integer) [Atomic mass \(: \mathrm{Na}=23.0, \mathrm{O}=16.0, \mathrm{H}=1.0]\)
- A \(62\)
- B \(13\)
- C \(20\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(13\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Na}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{NaOH}\) \(\frac{20}{62} \mathrm{moles}\) Moles of \(\mathrm{NaOH}\) formed \(=\frac{20}{62} \times 2\)…
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