JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
A mixture of \(1\) mole of \(H _2 O\) and \(1\) mole of \(CO\) is taken in a \(10\) litre container and heated to \(725\,K\). At equilibrium \(40 \%\) of water by mass reacts with carbon monoxide according to the equation : \(CO ( g )+ H _2 O ( g ) \rightleftharpoons CO _2( g )+ H _2( g )\) The equilibrium constant \(K _{ C } \times 10^2\) for the reaction is \(.......\) (Nearest integer)
- A \(41\)
- B \(42\)
- C \(43\)
- D \(44\)
Answer & Solution
Correct Answer
(D) \(44\)
Step-by-step Solution
Detailed explanation
\(CO _{( g )}+ H _2 O _{( g )} \rightleftharpoons CO _{2( g )}+ H _{2( g )}\) \(\begin{array}{lllll} t =0 & 1\,mol & 1\,mol & 0 & 0\end{array}\) at equ. \(1- x \quad 1- x \quad x \quad x\) at equilibrium \(40 \%\) by mass water reacts with \(CO\) \(x=0.4 \quad 1-x=0.6\)…
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