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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2024
  • Medium
  • Numerical

A tuning fork resonates with a sonometer wire of length \(1 \mathrm{~m}\) stretched with a tension of \(6 \mathrm{~N}\). When the tension in the wire is changed to \(54 \mathrm{~N}\), the same tuning fork produces \(12\) beats per second with it. The frequency of the tuning fork is _______ \(\mathrm{Hz}\).

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Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

\(\mathrm{f}=\frac{1}{2 L} \sqrt{\frac{T}{\mu}}\)

\(\mathrm{f}_1=\frac{1}{2} \sqrt{\frac{6}{\mu}} \mathrm{f}_2=\frac{1}{2} \sqrt{\frac{54}{\mu}}\)

\(\frac{\mathrm{f}_1}{\mathrm{f}_2}=\frac{1}{3} \mathrm{f}_2-\mathrm{f}_1=12\)

\(\mathrm{f}_1=6 \mathrm{HZ}\)

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