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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

A chromium complex with a formula \(CrCl _3 \cdot 6 H _2 O\) has a spin only magnetic moment value of 3.87 BM and its solution conductivity corresponds to \(1: 2\) electrolyte. 2.75 g of the complex solution was initially passed through a cation exchanger. The solution obtained after the process was reacted with excess of \(AgNO _3\). The amount of AgCl formed in the above process is __________ g. (Nearest integer)
[Given : Molar mass in \(g~mol ^{-1} Cr : 52 ; Cl : 35.5\), \(Ag : 108, O : 16, H : 1]\)

  1. A 3
  2. B 1
  3. C 6
  4. D 10
Verified Solution

Answer & Solution

Correct Answer

(A) 3

Step-by-step Solution

Detailed explanation

\(\begin{array}{lc}{\left[ Cr \left( H _2 O \right)_5 Cl \right] Cl _2 \cdot H _2 O + AgNO _3} & \rightarrow 2 AgCl \\ 2.75 / 266.5 & - \\ =0.0103 \text { moles } & 0.02063 \text { mole }\end{array}\) Mass of \(AgCl =0.02063 \times 143.5=2.96 gm\)
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