ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2020
  • Medium
  • MCQ

If momentum \((P),\) area \((A)\) and time \((T)\) are taken to be the fundamental quantities then the dimensional formula for energy is :

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left[ PA ^{1 / 2} T ^{-1}\right]\)

Step-by-step Solution

Detailed explanation

Let \([ E ]=[ P ]^{ x }[ A ]^{ y }[ T ]^{z}\)

\(ML ^{2} T ^{-2}=\left[ MLT ^{-1}\right]^{ x }\left[ L ^{2}\right] y [ T ]^{z}\)

\(ML ^{2} T ^{-2}= M ^{ x } L ^{ x +2 y } T ^{- x +z}\)

\(\rightarrow x =1\)

\(\rightarrow x +2 y =2\)

\(1+2 y =2\)

\(y =\frac{1}{2}\)

\(\rightarrow- x + z =-2\)

\(-1+ z =-2\)

\(z =-1\)

\([ E ]=\left[ P A ^{1 / 2} T ^{-1}\right]\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app