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JEE Mains · Chemistry · STD 11 - 7. Redox reactions

\(20\,mL\) of \(0.02\,M\) hypo solution is used for the titration of \(10\,mL\) of copper sulphate solution, in the presence of excess of \(KI\) using starch as an indicator. The molarity of \(Cu ^{2+}\) is found to be \(\times 10^{-2}\,M\)[nearest integer]Given : \(2 Cu ^{2+}+4 I ^{-} \rightarrow Cu _{2} I _{2}+ I _{2}\) \(I _{2}+2 S _{2} O _{3}{ }^{2-} \rightarrow 2 I ^{-}+ S _{4} O _{6}{ }^{2-}\)

  1. A \(3\)
  2. B \(4\)
  3. C \(5\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

\(n _{\text {eq. }}\) of \(I _{2}= n _{ eq }\) of \(Na _{2} S _{2} O _{3}=20 \times 0.002 \times 1\) \(2 \times n _{ mol }\) of \(I _{2}=0.4\) \(n _{ mol }\) of \(I _{2}=0.2 m mol\) \(n _{ mol }\) of \(Cu ^{+2}=0.2 \times 2 \times 10^{-3}\)…
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