JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2025
- Easy
- MCQ
Match the LIST-I with LIST-II
| LIST-I | LIST-II | ||
| A. | Pressure varies inversely with volume of an ideal gas | I. | Adiabatic process |
| B. | Heat absorbed goes partly to increase internal energy and partly to do work | II. | Isochoric process |
| C. | Heat is neither absorbed nor released by a system | III. | Isothermal process |
| D. | No work is done on or by a gas | IV. | Isobaric process |
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) A-III, B-IV, C-I, D-II
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{A} \rightarrow \mathrm{P} \propto \frac{1}{\mathrm{~V}} \\
& \Rightarrow \mathrm{PV}=\text { constant } \\
& \Rightarrow \mathrm{nRT}=\text { const. } \Rightarrow \mathrm{T}=\text { const. }
\end{aligned}\)
Hence Isothermal III
B \(\rightarrow\) IV
\(\mathrm{W} \neq 0, \Delta \mathrm{U} \neq 0, \Delta \mathrm{Q} \neq 0\) [only isobaric]
\(\mathrm{C} \rightarrow \mathrm{I} \Delta \mathrm{Q}=0\) Adiabatic
\(\mathrm{D} \rightarrow\) II w \(=0\) Isochoric
III, IV, I, II
& \mathrm{A} \rightarrow \mathrm{P} \propto \frac{1}{\mathrm{~V}} \\
& \Rightarrow \mathrm{PV}=\text { constant } \\
& \Rightarrow \mathrm{nRT}=\text { const. } \Rightarrow \mathrm{T}=\text { const. }
\end{aligned}\)
Hence Isothermal III
B \(\rightarrow\) IV
\(\mathrm{W} \neq 0, \Delta \mathrm{U} \neq 0, \Delta \mathrm{Q} \neq 0\) [only isobaric]
\(\mathrm{C} \rightarrow \mathrm{I} \Delta \mathrm{Q}=0\) Adiabatic
\(\mathrm{D} \rightarrow\) II w \(=0\) Isochoric
III, IV, I, II
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