JEE Mains · Chemistry · STD 11 - 2. structure of atom
Match the LIST-I with LIST-II
| List-I Orbital | List-II Radial nodes and nodal plane |
|---|---|
| A. \(2s\) | I. \(1\) Radial node + two nodal planes |
| B. \(3s\) | II. \(1\) Radial node + one nodal plane |
| C. \(3p\) | III. \(2\) Radial nodes + No nodal plane |
| D. \(4d\) | IV. \(1\) Radial node + No nodal plane |
Choose the correct answer from the options given below:
- A A-IV, B-I, C-III, D-II
- B A-IV, B-II, C-III, D-I
- C A-III, B-I, C-IV, D-II
- D A-IV, B-III, C-II, D-I
Answer & Solution
Correct Answer
(D) A-IV, B-III, C-II, D-I
Step-by-step Solution
Detailed explanation
The number of radial nodes is given by the formula \(n - l - 1\). The number of nodal planes (angular nodes) is given by \(l\). For \(2s\) orbital: \(n = 2\), \(l = 0\). Radial nodes = \(2 - 0 - 1 = 1\). Nodal planes = \(0\). This matches A with IV. For \(3s\) orbital:…
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