JEE Mains · Physics · STD 12 - 13. Nuclei
In a radioactive decay chain, the initial nucleus is \({}_{90}^{232}Th\). At the end there are \(6\,\,\alpha -\) particles and \(4\,\,\beta -\) particles with are emitted. If the end nucleus is \({}_Z^AX\,,\,A\) and \(Z\) are given by
- A \(A = 208;\,\,Z = 80\)
- B \(A = 202;\,\,Z = 80\)
- C \(A = 208;\,\,Z = 82\)
- D \(A = 200;\,\,Z = 81\)
Answer & Solution
Correct Answer
(C) \(A = 208;\,\,Z = 82\)
Step-by-step Solution
Detailed explanation
\({}_{90}^{232}Th\,\,\xrightarrow{{6\alpha }}\,{}_{78}^{208}Y\,\xrightarrow{{4\beta }}\,{}_{82}^{208}X\)
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