JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(1\, gram\) of a carbonate \((M_2CO_3)\) on treatment with excess \(HCl\) produces \(0.01186\, mole\) of \(CO_2.\) The molar mass of \(M_2CO_3\) in \(g\, mol^{-1}\) is :
- A \(1186\)
- B \(84.3\)
- C \(118.6\)
- D \(11.86\)
Answer & Solution
Correct Answer
(B) \(84.3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{M}_{2} \mathrm{CO}_{3}+2 \mathrm{HCl} \rightarrow 2 \mathrm{MCl}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2}\) \(n=\frac{\text { Mass given }}{\text { Molar mass }}\) \(0.01186=\frac{1}{M} \Rightarrow M=84.3\, \mathrm{g\,mol}^{-1}\)
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