JEE Mains · Chemistry · STD 11 - 2. structure of atom
The number of correct statements from the following \(A.\) For 1 s orbital, the probability density is maximum at the nucleus. \(B.\) For \(2 s\) orbital, the probability density first increases to maximum and then decreases sharply to zero. \(C.\) Boundary surface diagrams of the orbitals encloses a region of \(100 \%\) probability of finding the electron. \(D.\) \(p\) and d-orbitals have \(1\) and \(2\) angular nodes respectively. \(E.\) Probability density of p-orbital is zero at the nucleus.
- A \(3\)
- B \(4\)
- C \(2\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(A, D\) and \(E\) statements are correct. For \(2 s\) orbital, the probability density first decreases and then increases. At any distance from nucleus the probability density of finding electron is never zero and it always have some finite value.
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