JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
If the boiling points of two solvents \(X\) and \(Y\) (having same molecular weights) are in the ratio \(2 : 1\) and their enthalpy of vaporizations are in the ratio \(1: 2\), then the boiling point elevation constant of \(X\) is \(\underline{ m }\) times the boiling point elevation constant of \(Y\). The value of \(m\) is \(.....\). (Nearest integer)
- A \(8\)
- B \(6\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(\frac{\left( T _{ B }\right)_{ x }}{\left( T _{ B }\right)_{ y }}=\frac{2}{1} \quad \frac{(\Delta H )_{ x }}{(\Delta H )_{ y }}=\frac{1}{2}\)…
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