JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Excess of \(NaOH\, (aq)\) was added to \(100\, mL\) of \(FeCl_3\, (aq)\) resulting into \(2.14\, g\) of \(Fe(OH)_3\) .The molarity of \(FeCl_3\, (aq)\) is (Given molar mass of \(Fe=56\, g\, mol^{-1}\) and molar mass of .............. \(\mathrm{M}\) (\(Cl=35.5\, g\, mol^{-1}\))
- A \(0.2\)
- B \(0.3\)
- C \(0.6\)
- D \(1.8\)
Answer & Solution
Correct Answer
(A) \(0.2\)
Step-by-step Solution
Detailed explanation
\(\underset{\begin{smallmatrix} \lim iting \\ reagent \end{smallmatrix}}{\mathop{FeC{{l}_{3}}(aq.)}}\,+\underset{\begin{smallmatrix} (Excess\,amount) \\ not\,behave\,as \\ \lim iting\,reagent \end{smallmatrix}}{\mathop{3NaOH(aq.)}}\,\to \) \(Fe{(OH)_3}(s) + 3NaCl(aq.)\) Moles of…
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