JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
\(0.2 \%(\mathrm{w} / \mathrm{v})\) solution of NaOH is measured to have resistivity \(870.0 \mathrm{~m} \Omega \mathrm{~m}\). The molar conductivity of the solution will be ______ \(\times 10^2 \mathrm{mS} \mathrm{dm}{ }^2 \mathrm{~mol}^{-1}\). (Nearest integer)
- A 20
- B 23
- C 26
- D 29
Answer & Solution
Correct Answer
(B) 23
Step-by-step Solution
Detailed explanation
Given : Concentration of \(\mathrm{NaOH}=0.2 \%(\mathrm{w} / \mathrm{v})\) \(\therefore 0.2 \mathrm{~g}\) of NaOH in 100 ml of solution. Molarity of NaOH solution…
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